8x^(1/2)-x-40=0

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Solution for 8x^(1/2)-x-40=0 equation: 


D( x )

x < 0

x < 0

x in <0:+oo)

8*x^(1/2)-x-40 = 0

t_1 = x^(1/2)

8*t_1^1-1*t_1^2-40 = 0

8*t_1-t_1^2-40 = 0

DELTA = 8^2-(-40*(-1)*4)

DELTA = -96

DELTA < 0

x belongs to the empty set

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